Azathothas
Tested the published **wsl-toolkit-v1.3.0 Windows amd64** binary on Windows 11/WSL2 on 2026-09-10. SHA-256: `71b2ef9b0cf50da0acda45e7cc9293185a2b18d8aa403812e20ed29222d54424`, matching the release manifest. Related: #6. ## Summary `base shell` and `base shell --root` start in the caller's Windows working directory mounted under `/mnt/c`, not in the distro user's home. The root shell can therefore modify/delete the host checkout. The manual's warning says root is “inside the distribution” and “not on this machine,” which gives the opposite safety impression. ## Reproduction From the repository directory: ```powershell Set-Location C:\Users\AjamX\Downloads\ToolKit & $wtk base shell & $wtk base shell --root ``` Inside both shells: ```sh pwd findmnt -T . test -w .; echo $? ``` Observed: `pwd` was `/mnt/c/Users/AjamX/Downloads/ToolKit`; `findmnt` identified `/mnt/c` as a writable 9p/drvfs mount; the directory was writable. I did not mutate the repository. This does not affect isolated `run` containers, which correctly receive a copied workspace and no host mount. It affects the explicitly offered base shell. ## Cause The shell implementation invokes `wsl.exe -d <base> -u <user>` without `--cd` or a guest-side `cd`. WSL inherits/translates the host current directory. ## Expected Default to the selected guest user's home (for example `--cd ~`) or make host-cwd attachment an explicit opt-in. The root warning must state plainly whenever Windows drives are mounted and writable. Add an acceptance assertion that a shell launched from a host checkout does not begin inside that checkout by default.