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slacktracer avatar slacktracer commented on July 22, 2024

My take,

Your example, @CoderK, just gets to the same result value but doesn't show how things work "inside" ES6.

When the comment says "y is an array" it's showing how ES6 behaves. Every argument past the first one becomes (in this specific example, using (x, ...y)) part of an array.

The example seems to have changed since the creation of this issue but the point remains. At the moment every argument past the first is part of an array you're in pretty much the same place as you would be with ...y in ES6.

The example now uses var y = []; y.push.apply(y, arguments) && y.shift(); Another way to make y a true array of all arguments past the first.

Wow, I repeated myself a lot. =P
I'll stop.

Let me know if I didn't made myself clear enough, or at all. =P
Thanks.

from es6-equivalents-in-es5.

CoderK avatar CoderK commented on July 22, 2024

Wow, I got it.
Thanks for your reply.

I'm going to close this issue.

from es6-equivalents-in-es5.

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