Sunset time calculation with swe.rise_trans broken about pyswisseph

[astrorigin]

Inspect the whole result:

jd_sunset = swe.rise_trans(jd_start=2457753.5, body=swe.SUN, lon=13.09,
... lat=80.27, rsmi=swe.CALC_SET | swe.BIT_DISC_CENTER)
jd_sunset
((-2,), (0.0, 2.695100435457e-312, 2.7874627029316465e-291, 1.818790777727e-311, 2.7874625367389016e-291, 9.766745e-317, 4.343725384106e-311, 5.2865984597206454e-303, 9.76668e-317, nan))

Function has returned (-2), object is circumpolar

By exchanging lon/lat you get:

jd_sunset = swe.rise_trans(jd_start=2457753.5, body=swe.SUN, lon=80.27,
... lat=13.09, rsmi=swe.CALC_SET | swe.BIT_DISC_CENTER)
jd_sunset
((0,), (2457754.015392543, 2.695100435457e-312, 2.7874627029316465e-291, 3.84528846805e-313, 2.7874625367389016e-291, 9.746423e-317, 4.343725384106e-311, 5.2865976774675737e-303, 9.7666284e-317, nan))

[vvasuki]

Oh! I was beyond the arctic circle!
Sorry for the false alarm. 🙏
Wouldn't it be better to raise an exception in such a case though?

[astrorigin]

http://www.astro.com/swisseph/swephprg.htm#_Toc471829085

Conforming to the docs, an exception/error is raised if returned result is (-1) (internal - calc or ephemeris error)

In my opinion you could raise an exception on your side if you find returned result[0][0]==-2

And double-check your input variables

[vvasuki]

OK, Thanks!