Comments (2)
For reference, here's a link to the line of code you're referring to.
You're right there will never be duplicate keys, but here we're starting the index at the hash slot and looping till either we find an empty slot (the while (entries[index].key != NULL)
) or we find that the key is already present in the map (the line you mentioned). So this line of code is needed in case the key is already present in the map, in which case we just update its value.
Hope that helps!
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Thanks for the clarification.
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