- Develop a rest service that uses this Order API (link) and, based on the result, filters by data according to the parameters sent by HTTP request. The service must follow this definition:
GET http://localhost:8080/challenge-backend/item?begindate=05-10-2016&finaldate=10-10-2016
[
{
"name": "Impressora",
"code": "5",
"date": "2016-10-05T14:30:37.040Z",
"dimension": {
"weight": 10.5,
"height": 10.5,
"width": 10.5,
"length": 10.5
}
},
{
"name": "Fifa2017",
"code": "6",
"date": "2016-10-06T14:30:37.040Z",
"dimension": {
"weight": 10.5,
"height": 10.5,
"width": 10.5,
"length": 10.5
}
},
.
.
.
]
- Quality and organization of the code;
- Pay attention to the requirements;
- Use Java 6 or newer (or Elixir language)
- The candidate can choose any framework
Do not forget to create a README to tell us how to run the project π
- Given a table events with the following structure:
create table events (
event_type integer not null,
value integer not null,
time timestamp not null,
unique (event_type, time)
);
write an SQL (MySQL) query that, for each event_type that has been registered more than once, returns the difference between the penultimate and the oldest value (in terms of time) . The table should be ordered by event_type (in ascending order). For example, given the following data:
event_type | value | time |
---|---|---|
2 | 5 | 2015-05-09 12:42:00 |
4 | -42 | 2015-05-09 13:19:57 |
2 | 2 | 2015-05-09 14:48:30 |
2 | 7 | 2015-05-09 12:54:39 |
3 | 16 | 2015-05-09 13:19:57 |
3 | 20 | 2015-05-09 15:01:09 |
Your query should return the following rowset:
event_type | value |
---|---|
2 | 2 |
3 | 0 |
For example, for the event_type 2, the penultimate value is a 7 and the oldest value is 5, so the difference between them is 2. The name of the columns in the rowset donβt matter, but their order does.
- See the directory task2 to solve the second question
- Create a file and put the result of the query
Create a Fork of this project and send us a pull request