Comments (1)
Oi, @Joaolucasos169. Tudo certinho?
Então, é bem simples:
A variável que irá receber a entrada do teclado, você a chamou de entrada
:
Scanner entrada = new Scanner(System.in);
Porém, quando de fato você quer pegar a entrada, você está chamando a variável de teclado
. Acredito que você tenha confundido já que nas aulas, eu quem chamei de teclado
, né? hehe
Tenta o seguinte: char turno = entrada.nextLine().charAt(0);
Outro detalhe, note que ao final da estrutura de decisão, você precisa imprimir o valor armazenado na variável mensagem
. E no código que você me mostrou aqui, só está imprimindo apenas essa linha: System.out.println("**********");
Caso ainda ficou alguma dúvida, sigo à disposição! (:
from logica_de_programacao_essencial.
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