Link in the text about rss-parser

[dhvcc]

I think it is being discarded by bs4 because is a tag and bs4 only gives back the text between the tag. Looking at the documentation, it should give back the raw text with tags and I do not see anywhere in the code where the rss parser deletes them. Also @dhvcc , since January you did not do a release, I would appreciate one on Pypi when this issue is resolved! 👍 I did not even recognise that it did not update because I kept using my hacky workaround in my code 😅

Yeah, will do one for sure. Thanks for using the package

[BBArikL]

So, while looking back at the code to make it ready for the next release I remembered that even if bs4 does strip out html tags ( with href and ), the parser does make a search for them so it wont appear in the description itself, but it should appear as one of the values of the attribute description_links. But if you really want to know the text that was marked by the tags then @dhvcc 's example could work.

[dhvcc]

Could you please send an example of this RSS feed?

[Phantomik]

https://philthyboys.ru/data/rss

[dhvcc]

https://philthyboys.ru/data/rss

I'll check this one today

[BBArikL]

I think it is being discarded by bs4 because is a tag and bs4 only gives back the text between the tag. Looking at the documentation, it should give back the raw text with tags and I do not see anywhere in the code where the rss parser deletes them. Also @dhvcc , since January you did not do a release, I would appreciate one on Pypi when this issue is resolved! 👍 I did not even recognise that it did not update because I kept using my hacky workaround in my code 😅

[dhvcc]

Hey @Phantomik. As far as I can see - these are not valid "tags" in RSS, hence, they are treated as text and escaped. You can try to unescape them if you really want too, but then you'd have to work with bs4 manually. Something like this could do the trick (note, that this is a mock up of a code and I did not test it myself)

from xml.sax.saxutils import unescape
from bs4 import BeautifulSoup
...
feed = parser.parse()
# Iteratively print feed items
for item in feed.feed:
    soup = BeautifulSoup(unescape(item.description))
    print(soup.find_all('a'))

[dhvcc]

Please, make sure to close the issue if you fell like it was resolved. I'll push a release after that @BBArikL

[Phantomik]

Thank you @dhvcc . The guys and I decided to leave it as it is for now. And write your own parser so that there are links and pictures. Later I will check your guess and write.