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Dod-o avatar Dod-o commented on May 18, 2024

明白了你的意思,实际代码应该按你的想法去写,不过这样子时间复杂度上需要再乘上一个n的平方,也许会被无法接受。
实际上目前E的值像进度条一样更新,当前位置i的E是刚更新的,最可靠的,离当前位置i越远越不可靠,但随着迭代轮数的增加,整个模型会趋于稳定,每次更新alpha后对E的影响也就越来越小。
这是对时间的一种折中,我相信按照你说的做法实际迭代所需轮数可能会小一点,但多走几个轮数,让模型自己趋于稳定也一样可以,虽然轮数增加了,但我相信总时间会少很多很多。

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