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GoogleCodeExporter avatar GoogleCodeExporter commented on August 29, 2024
Looks like the parser expects every expression tree to be an array, but the 
code for parsing an "AGAINST" clause will return a single value rather than an 
array if the contents are a single value (on line 1112):

$processed = $list[0];

Changing this to return an array will fix the glitch for your particular code 
sample:

$processed = array($list[0]);

Regarding the print_r: It looks like the author put the print_r in there 
because that is an exceptional case that should normally never occur and 
signals a parsing bug.  But since you have the source code you can just comment 
it out :-)

It looks like there's another debug statement that occurs on lines 165-169 if 
the argument to parse is not a string:

if(!is_string($sql)) {
    echo "SQL:\n";
    print_r($sql);
    exit;
}

Original comment by [email protected] on 20 Oct 2011 at 5:16

from php-sql-parser.

GoogleCodeExporter avatar GoogleCodeExporter commented on August 29, 2024
I think, I have solved the parsing problem described by this issue.
Check out the bleeding edge on 
https://www.phosco.info/publicsvn/php-sql-parser/trunk/

Original comment by [email protected] on 17 Feb 2012 at 1:09

from php-sql-parser.

GoogleCodeExporter avatar GoogleCodeExporter commented on August 29, 2024
Accepted fixed codebase.

Original comment by [email protected] on 12 Mar 2012 at 9:56

  • Changed state: Fixed

from php-sql-parser.

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