Problem with Python3.2 about howdoi

[gleitz]

Thanks for the bug report. What is the howdoi command you are running? I just tried the latest version from master and it appears to be working:

$ python3 howdoi/howdoi.py format date bash
DATE=`date +%Y-%m-%d`

[keelzebub]

It's happening with me, too - using the command "howdoi perl join", with python verson 3.2.3

[gleitz]

Aha. I am using Python 3.3. Let me see if I can install Python 3.2 and figure out what the issue is...

[gleitz]

I'm guessing this is the issue

Unicode literals causing invalid syntax

[gleitz]

I believe the following steps will fix the issue:

• Please change all instances of u"foo" to "foo"
• Put this at the top of the file: from __future__ import unicode_literals

Please let me know if that works for you and I'll add it to the main codebase.

[gleitz]

And here is why I was not seeing an issue with Python 3.3 but you do in 3.2

http://www.python.org/dev/peps/pep-0414/

[kensington]

Sorry, I should have mentioned originally that Python3.3 did work fine. With the changes suggested above it's working with Python3.2.

[gleitz]

Perfect. Thanks for your help! I'll check in the changes and do a point release

[gleitz]

When I added from __future__ import unicode_literals I got the following error in Python2. Seems to be an issue with lxml (used by PyQuery)

$ python howdoi/howdoi.py get this to work in python3
Traceback (most recent call last):
  File "howdoi/howdoi.py", line 168, in <module>
    command_line_runner()
  File "howdoi/howdoi.py", line 165, in command_line_runner
    print(howdoi(args))
  File "howdoi/howdoi.py", line 142, in howdoi
    return get_instructions(args) or 'Sorry, couldn\'t find any help with that topic\n'
  File "howdoi/howdoi.py", line 120, in get_instructions
    links = get_links(args['query'])
  File "howdoi/howdoi.py", line 48, in get_links
    return [a.attrib['href'] for a in html('.l')]
  File "lxml.etree.pyx", line 2261, in lxml.etree._Attrib.__getitem__ (src/lxml/lxml.etree.c:53908)
KeyError: u'href'

However it turns out I don't need Unicode strings at all so I just removed all the references to u'foo'. I've merged the changes into the master branch and have updated pypi. Please let me know if you see any other issues.

[dnatag]

It seems Python 2.7 do need u'...', otherwise, you will get UnicodeEncodeError.
Try this query: howdoi.py -n3 python unittest
I got:
Traceback (most recent call last):
File "howdoi.py", line 166, in
command_line_runner()
File "howdoi.py", line 163, in command_line_runner
print(howdoi(args))
File "howdoi.py", line 140, in howdoi
return get_instructions(args) or 'Sorry, couldn't find any help with that topic\n'
File "howdoi.py", line 131, in get_instructions
answer = ANSWER_HEADER.format(current_position, answer)
UnicodeEncodeError: 'ascii' codec can't encode character u'\u2019' in position 350: ordinal not in range(128)

[kensington]

Cannot reproduce previous comment with Python 2.7 and howdoi 1.1.2

[gleitz]

I'm having difficulty as well. Would to please provide an example that
breaks?
On Mar 22, 2013 10:44 AM, "kensington" [email protected] wrote:

Cannot reproduce previous comment with Python 2.7 and howdoi 1.1.2

—
Reply to this email directly or view it on GitHubhttps://github.com//issues/52#issuecomment-15307558
.

[dnatag]

Here is the query and I am using latest git copy of howdoi.py. Not sure the version number.
howdoi -n 3 python unittest

[gleitz]

Thanks for pointing out the issue, @dnatag. I've submitted a fix to the master branch as well as a test for this error.

Please let me know if you run into any more issues.