Equations: multiply by x on both sides about mathsteps

[arbylee]

Hi there, I'm interested in taking a crack at this if it's not assigned

[evykassirer]

That would be fantastic, thank you! This will help us solve a lot more equations than we were able to before.

Let me know if you have any questions or encounter anything tricky

[arbylee]

I got a basic case working, but am questioning my approach as I try to get the more complex case working. I'd like to hear your thoughts

Symbols.getLastSymbolTerm currently relies on Node.PolynomialTerm.isPolynomialTerm to find the last symbol term. It doesn't recognize terms such as 1/(2+x) because it's not definitionally a polynomial term. I'm not planning on changing isPolynomialTerm, but I've started to enhance Symbols.getLastSymbolTerm and the helper function isSymbolTerm to recognize 1/(2+x) as a symbol term. I'm currently planning something like Symbols.getLastSymbolTerm on 3/(x^2 + 3) to return 1/(x^2 + 3) I'm wondering if that's dirtying the definition of "symbol term" or if you have some other approach in mind

[evykassirer]

Yeah I had a feeling this had some trickiness to it haha.

Good idea - I think that makes sense (and if it doesn't, we can move that functionality to a different place so feel free to write it out now). Perhaps this function shouldn't live in Symbols and should be in a more equation specific file. What do you think?

I'd also like to bring @aelnaiem into the conversation too if he's free/interested, cause he wrote most of the equation code and might have some opinions on stuff.