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hofmannmartin avatar hofmannmartin commented on August 22, 2024

Not out of the box. Currently, our package contains methods to work with expansions of solid harmonics (r^nYlm, n>=0).

As I understand it you would need to work with n<=0. This possibility is not implemented. However, our package provides methods to analytically generate the Ylm as a starting point. There is a small documentation available, which can be found here.

from sphericalharmonicexpansions.jl.

tmamedzadeh avatar tmamedzadeh commented on August 22, 2024

No, I need to calculate the derivative of this. Is it posible?

from sphericalharmonicexpansions.jl.

hofmannmartin avatar hofmannmartin commented on August 22, 2024

I doubt it, since your expression is no polynomial.

from sphericalharmonicexpansions.jl.

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