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hs-lsong avatar hs-lsong commented on July 23, 2024

I can't get this. why the second {{ foo() }} only outputs 1 instead of 1 2? What would be output of a third {{ foo() }} ?

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jasmith-hs avatar jasmith-hs commented on July 23, 2024

The second {{ foo() }} is not supposed to output 1, the reason it does it because the macro's definition will get overwritten while evaluating the first {{ foo() }}. It will then call the child foo() on subsequent calls, and only return 1. It will continue to return 1 for the third, fourth, etc calls because the macro function will be overwritten

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jasmith-hs avatar jasmith-hs commented on July 23, 2024

In jinja, the child macro function's definition does not change the macro functions defined on the global scope, but in jinja, then the definition can impact the global macro functions defined on outer scopes.

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hs-lsong avatar hs-lsong commented on July 23, 2024

πŸ‘

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