Comments (8)
Here is an example where animationStartValue
works fine at the first time. Or have I misunderstood you?
from jquery-circle-progress.
@coolara - has it solved your problem?
from jquery-circle-progress.
Not yet. The problem still exists
from jquery-circle-progress.
Do you have this problem with my demo? Could you, please, give me a code example of the problem or to explain it more?
from jquery-circle-progress.
$.rotate({value: 0.8, time: 3, animationStartValue: 0.2});
$.rotate = function (obj) {
var rotate = $("<div class='bg'></div>"
+ "<div id='circle'>"
+ "</div>");
$("#rotate").append(rotate);
$('#circle').circleProgress({
value: obj.value,
size: 250,
fill: {
gradient: ["#5DC0FF", "#A5D0DC"]
},
emptyFill: "rgba(250, 250, 250, .1)",
startAngle: -Math.PI / 2,
thickness: 10,
lineCap: "round",
animation: {
duration: obj.time * 1000
},
animationStartValue: obj.animationStartValue
});
};
from jquery-circle-progress.
second do this funciton ,
first do this function
from jquery-circle-progress.
According to your code:
- each time you call
$.rotate(...)
- you insert new<div id="circle">
into<div id="rotate">
- then you do
$("#circle").circleProgress(...)
. - jQuery finds not the newly inserted
<div id="circle">
but the "old" one (the first one)
This is probably not what you want and the reason of your problem.
I don't 100% understand what you're trying to do, so I give you two solutions:
- If you want to create a circle each time you call
$.rotate(...)
- solution 1 - If you want to re-use the same circle and just to restart its animation when you call
$.rotate(...)
- solution 2
from jquery-circle-progress.
Thank you for solving my problem, It runs correctly
from jquery-circle-progress.
Related Issues (20)
- Adding to Google Web Designer
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from jquery-circle-progress.