Comments (3)
进事件方法,直接返回啊
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进事件方法,直接返回啊
form.on('checkbox(demo-checkbox-filter)', function(data){
return false;//是这个吗?
var elem = data.elem; // 获得 checkbox 原始 DOM 对象
var checked = elem.checked; // 获得 checkbox 选中状态
var value = elem.value; // 获得 checkbox 值
var othis = data.othis; // 获得 checkbox 元素被替换后的 jQuery 对象
layer.msg('checked 状态: '+ elem.checked);
});
请问是直接 return false;
吗?加上之后,后面的代码不执行了,但是页面上的按钮还是可以点击切换状态
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@SouSuoKe 你好,为了提升沟通效率,我们对 Issue 制定了严格的要求,你的 Issue 因不符合规定而被自动关闭。
建议你在下次创建 Issue 时,遵循相应规范和社区行为准则。谢谢。
详见:🍀 Layui Issue 贡献指南
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