How to dismiss menu programmatically? about ybpopupmenu

[lyb5834]

well, YBPopupMenu's superView is the main window, so you can refer to the following code

[[UIApplication sharedApplication].delegate.window.subviews enumerateObjectsUsingBlock:^(__kindof UIView * _Nonnull obj, NSUInteger idx, BOOL * _Nonnull stop) {
        
       if ([obj isMemberOfClass:[YBPopupMenu class]]) {
           YBPopupMenu * popupMenu = (YBPopupMenu *)obj;
           [popupMenu dismiss];
       }
        
}];

[lyb5834]

    YBPopupMenu * popupMenu = [YBPopupMenu showAtPoint:point titles:TITLES icons:nil 
      menuWidth:110 otherSettings:^(YBPopupMenu *popupMenu) {
        popupMenu.dismissOnSelected = YES;
        popupMenu.xxx
        ...
    }];
    [popupMenu dismiss];

you can try this function

[skuske]

@lyb5834

Thanks for your rapid reply.

Unfortunately this does not work, as I want to call dismiss from inside viewWillDisappear, otherwise a menu that is currently open will remain visible even after the containing ViewController has been dismissed.

What I want o achieve is: close all menus that might still be open, then dismiss the ViewController...

[skuske]

@lyb5834

Cool, many thanks.