What is syntax to create sprite? about m5unified

[patfelst]

Thanks. I didn't know you could push a sprite to display in another sprite. I don't need to do it now, but am curious. Would it work like this?

#include <M5Unified.h>

M5Canvas SpriteA;
M5Canvas SpriteB;

void setup(void)
{
  M5.begin();
  SpriteA.createSprite(32, 32);
  SpriteA.drawCircle(16, 16, 10, TFT_WHITE);

  SpriteB.createSprite(100, 100);
  SpriteA.pushSprite(&SpriteB, 32, 32); // Draw SpriteA inside SpriteB
  SpriteB.pushSprite(&M5.Display, 0, 0);
}

[lovyan03]

@patfelst
Yes, that's correct.
If you are interested, take a look at the LovyanGFX sample.

https://github.com/lovyan03/LovyanGFX/blob/0.4.7/examples/Sprite/ClockSample/ClockSample.ino

The entity of M5.Display is the M5GFX library, and M5GFX is a wrapping of LovyanGFX.

[patfelst]

Actually they all compile, but the first and last both cuase the ESP32 to crash. The middle one works ok.

[lovyan03]

@patfelst
It is as per the specification.
When using pushSprite, you can set the output destination as the first argument.
In other words, in addition to output from M5Canvas to M5.Display, you can also output from M5Canvas to other M5Canvas.
If you specify the output destination in the constructor argument, you do not need to specify the output destination when using pushSprite, but you can specify the output destination if necessary.
In other words, if you omit the output destination in the constructor argument, you must always specify the output destination as the first argument when using pushSprite.

#include <M5Unified.h>

M5Canvas canvas;   // Omit the output destination

void setup(void)
{
  M5.begin();
  canvas.createSprite(32, 32);
  canvas.drawCircle(16, 16, 10, TFT_WHITE);

  canvas.pushSprite(&M5.Display, 32, 32);  // OK

//canvas.pushSprite( 64, 64);  // Crash !
}

[patfelst]

Wow that clock example will take some study. But I get the idea of what you're doing with the sprites.