Comments (2)
To escape an extended character that is not in the Basic Multilingual
Plane, the character is represented as a twelve-character sequence,
encoding the UTF-16 surrogate pair. So, for example, a string
containing only the G clef character (U+1D11E) may be represented as
"\uD834\uDD1E".
通过查阅rfc4627,json 规范中明确说明如果要转义超过bmp的字符,通过 UTF-16 surrogate pair 来转义。编码的时候会再转化为unicode code point,再将其通过utf-8 规则编码为二进制。 并不是以utf-16 来编码。
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我理解这应该是一种解析规则,在python中直接打印‘\uD834\uDD1E‘ 是会报错的,但是直接打印\U1D11E 是可以的。bash shell 中同样前者显示乱码,后者正常显示字符。
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Related Issues (20)
- C++ 版本
- Tutorial3中关于首次调用lept_free()函数的问题
- tutorial2中非法的情况是不是没判断完全 HOT 5
- 关于tutorial02的一张图 HOT 1
- 关于生成字符串的问题
- 关于生成器对\u字符的处理
- 不是很理解判断字符tutorial02中连续判断数字的代码 (p++; ISDIGIT(*p); p++); HOT 2
- 关于Tutorial04中将Unicode字符转换为UTF-8存储的lept_encode_utf8的写法 HOT 1
- about tutorial07 function—lept_stringify_string. why not add ' \" ' because it's the begin or end mark for a string HOT 3
- 毛遂自荐一下 HOT 1
- 关于使用宏而不是内联函数的问题
- 关于tutorial2对含有前导零数字处理的问题 HOT 1
- 指数解析出现问题, HOT 2
- C++ 版本(含详细注解~)
- https://github.com/Tencent/rapidjson
- 这里的为啥右移 HOT 1
- 关于第九章
- 'errno.h' 不是ANSI C的头文件 HOT 1
- 关于 tutorial2 中的这个 “0123”这个字符串的解析 HOT 1
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