Comments (1)
Compiling the code gives the following warning:
warning: unused `Result` that must be used
--> src/main.rs:25:5
|
25 | decoded_a.serialize(&mut &mut encoded_a.borrow_mut()[..]);
| ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
|
= note: `#[warn(unused_must_use)]` on by default
= note: this `Result` may be an `Err` variant, which should be handled
If you handle that result, you'll see that serialization actually errors. That is because you are trying to serialize to &mut &mut [u8]
, rather than &mut Vec<u8>
, which doesn't have enough space.
Here's a fixed example which works.
use borsh::{BorshDeserialize, BorshSerialize};
fn main() {
#[derive(BorshSerialize, BorshDeserialize, PartialEq, Debug)]
struct A {
x: u8,
y: Vec<String>,
}
let a = A {
x: 1,
y: vec!["cat".to_string()],
};
let encoded_a = a.try_to_vec().unwrap();
println!("Before: {:?}", encoded_a);
let mut decoded_a = A::try_from_slice(&encoded_a).unwrap();
println!("Decoded Before: {:?}", decoded_a);
decoded_a.x = 2;
decoded_a.y.push("dog".to_string());
let mut encoded_a = Vec::new();
decoded_a.serialize(&mut encoded_a).unwrap();
println!("After: {:?}", encoded_a);
let decoded2_a = A::try_from_slice(&encoded_a).unwrap();
println!("Decoded After: {:?}", decoded2_a);
}
Closing, as this is not a borsh bug, but rather a programming error which the compiler warns about.
from borsh-rs.
Related Issues (20)
- FR: Provide a way to borrow data from a slice. HOT 4
- Enum discriminant is not serialized when specified HOT 1
- Adding Async support HOT 14
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- Support for serde::{Serialize, Deserialize} HOT 7
- Add a test or two on `#[borsh_init(init)]` logic
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- Rename declarations (tuples, `nil`, `string`, `nonzero_xx` and arrays) HOT 5
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from borsh-rs.