Comments (1)
Usually, when you inherit from a single class, you can just use this.$super()
. When you have 2 parents and no diamond inheritance, to call the 2 constructors you have to simply call them using the classes prototypes:
var C = ring.create([A, B], {
init: function(x, y) {
A.prototype.init.call(this, x);
B.prototype.init.call(this, y);
}
});
If there is single inheritance, the constructors are supposed to have the same arguments. You can just call $super
:
var Z = ring.create({...});
var A = ring.create([Z], {...});
var B = ring.create([Z], {...});
var C = ring.create([A, B], {
init: function(x) {
this.$super(x);
}
});
The init
method of Z, A, B and C will all be called once, in the order of the method resolution order.
from ring.js.
Related Issues (14)
- Problem with length HOT 1
- Invoke Base Method HOT 2
- Ring along with others HOT 3
- Without underscore? HOT 9
- FAQ: How can this.$super possibly work w/o significant performance penalty? HOT 1
- Multiple inheritance method resolution HOT 4
- Static attributes HOT 1
- Static / Class variable inheritance support HOT 6
- Explanation of spec failure (bad equality) HOT 1
- Weird Constructor Name HOT 1
- How to achieve the private property HOT 1
- Recommended to increase the storage constructor parameters HOT 3
- Documentation link on homepage is a 404 HOT 1
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from ring.js.