GithubHelp home page GithubHelp logo

Comments (8)

jace-han avatar jace-han commented on August 11, 2024

Hello! The ArrayIndexOutOfBounds exception is raised as you are trying to access the first element ("Index 0 out of bounds") when the list is empty ("for length 0"). I can't really help for the loaders (marked by red boxes) just from expected and your output though.

from 2122-s2.

ldkai avatar ldkai commented on August 11, 2024

Hi! I ran into the same error as you, you may want to check if your code still runs normally for an empty cruise list

from 2122-s2.

Seibell avatar Seibell commented on August 11, 2024

I ran into the same error too so I just added a check for an empty cruise list before running code for level5

from 2122-s2.

tanweiming00 avatar tanweiming00 commented on August 11, 2024

One of the private test cases includes running an empty cruise list to the method. So your code must take into account of that!!

from 2122-s2.

jace-han avatar jace-han commented on August 11, 2024

To the comments above: If one is running a for loop iterating through the cruise list to "get" the cruises, would an empty cruise list throw an ArrayIndexOutOfBounds error? To my understanding, I don't think so because the for loop would just not be executed. Unless the iterator was set to <= list.size()

from 2122-s2.

shotnothing avatar shotnothing commented on August 11, 2024

If one is running a for loop iterating through the cruise list to "get" the cruises, would an empty cruise list throw an error? To my understanding, the for loop would just not be executed. Unless the iterator was set to <= list.size()

Yeah, the for loop is not executed, as it will immediately meet the condition < list.size().

It is specified the JLS:
https://docs.oracle.com/javase/specs/jls/se8/html/jls-14.html#jls-14.14.1.1

If the (possibly unboxed) value of the Expression is false the first time it is evaluated, then the Statement is not executed.

from 2122-s2.

undeser avatar undeser commented on August 11, 2024

Hey, the error you're experiencing is most likely happening because it is looping through an empty iterable. For my code, I actually implemented an if-else that if the iterable is empty, it will add something into it first before iterating through the iterable. Alternatively, you could use a do-while loop. Hope this helps.

from 2122-s2.

weekiatism avatar weekiatism commented on August 11, 2024

Codecrunch has a test case to check if the list is empty. Hence do check if the list is empty before looping through it. Using a while loop condition will make your code more elegant as compared to for loops.

from 2122-s2.

Related Issues (20)

Recommend Projects

  • React photo React

    A declarative, efficient, and flexible JavaScript library for building user interfaces.

  • Vue.js photo Vue.js

    πŸ–– Vue.js is a progressive, incrementally-adoptable JavaScript framework for building UI on the web.

  • Typescript photo Typescript

    TypeScript is a superset of JavaScript that compiles to clean JavaScript output.

  • TensorFlow photo TensorFlow

    An Open Source Machine Learning Framework for Everyone

  • Django photo Django

    The Web framework for perfectionists with deadlines.

  • D3 photo D3

    Bring data to life with SVG, Canvas and HTML. πŸ“ŠπŸ“ˆπŸŽ‰

Recommend Topics

  • javascript

    JavaScript (JS) is a lightweight interpreted programming language with first-class functions.

  • web

    Some thing interesting about web. New door for the world.

  • server

    A server is a program made to process requests and deliver data to clients.

  • Machine learning

    Machine learning is a way of modeling and interpreting data that allows a piece of software to respond intelligently.

  • Game

    Some thing interesting about game, make everyone happy.

Recommend Org

  • Facebook photo Facebook

    We are working to build community through open source technology. NB: members must have two-factor auth.

  • Microsoft photo Microsoft

    Open source projects and samples from Microsoft.

  • Google photo Google

    Google ❀️ Open Source for everyone.

  • D3 photo D3

    Data-Driven Documents codes.