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sholderbach avatar sholderbach commented on July 17, 2024 2

You are correct that if the second test (grapheme cluster boundary) is true the first one (UTF-8 char boundary) will always be true.

The first check is local and only needs to check the byte at the index (or length), while the follow-on second check requires us to traverse the string. Without benchmarking with real data (that is most likely valid), there could be a questionable argument about short-circuiting saving us the work for the second check. Given that we expect valid data anyways, we could probably elide the first check.

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