Comments (3)
Hi
Looking at example code you provided, it works as expected. any_invocable
without const
qualifier for its callable type is expected to be able to mutate itself when calling its operator()
(which is achieved by having only non-const operator()
in any_invocable
class definition for non-const callable type). That's why you cannot use it in const
member function of containing outer class.
To make this code work, either f
should have const
for it's callable type, or call()
should not have const
.
Looking now at godbolt example more.
from any_invocable.
I see the problem, will make fixing PR shortly.
from any_invocable.
Your example at https://godbolt.org/z/Wczddnsoh builds now.
from any_invocable.
Related Issues (4)
- Clarify license HOT 5
- std::vector incompatible? HOT 6
- Remove extra semicolons HOT 1
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from any_invocable.