1.1.8 Issue about laravel-follow

[davisriska]

Im sadly having the same issue, as Im also using MSSQL. Locking the version on 1.1.7 for now. If only I could use MySQL I would. 😢
@snazy2000 If you find a solution, please be so kind and post it here! 😅

[overtrue]

What db engine are you used?

[overtrue]

https://dev.mysql.com/doc/refman/8.0/en/working-with-null.html

IS NOT NULL is a valid mysql syntax.

[snazy2000]

Using mssql :( Sent from Yahoo Mail for iPhone On Friday, October 26, 2018, 2:47 pm, 安正超 <[email protected]> wrote: https://dev.mysql.com/doc/refman/8.0/en/working-with-null.html IS NOT NULL is a valid mysql syntax. — You are receiving this because you authored the thread. Reply to this email directly, view it on GitHub, or mute the thread.

[overtrue]

I got the reason. Sorry, I will fix that as soon as possible.

[overtrue]

@snazy2000 Plz take a try with master branch, plz let me know if it works.

[snazy2000]

Hi @overtrue

I have just tried the fix and unfortunately still same error.

It doesn't look like what your doing there is supported in MSSQL

Stephen

[snazy2000]

https://stackoverflow.com/questions/14962970/sql-query-if-value-is-null-then-return-1

[overtrue]

@snazy2000 Please paste the SQL.

[snazy2000]

select [users].*, [pivot_followables].[user_id] IS NOT NULL as [pivot_each_other], [followables].[followable_id] as [pivot_followable_id], [followables].[user_id] as [pivot_user_id], [followables].[followable_type] as [pivot_followable_type], [followables].[relation] as [pivot_relation], [followables].[created_at] as [pivot_created_at] from [users] inner join [followables] on [users].[id] = [followables].[user_id] left join [followables] as [pivot_followables] on [pivot_followables].[followable_type] = 'App\Suggestion' and [pivot_followables].[followable_id] = [followables].[user_id] and [pivot_followables].[user_id] = [followables].[followable_id] where [followables].[followable_id] = 1066 and [followables].[followable_type] = App\Suggestion and [followables].[relation] = follow

[overtrue]

@snazy2000 I am sorry, I have not SQL Server environment, So, plz do you best to debug and fix this problem, or use MySQL. Let me know if you resolved the bug. Thanks.

[snazy2000]

Can you advise what the need for the IS NOT NULL at that point?
If I remove it shows NULL in that field
Im used to the IS NOT NULL within the Where statements

[overtrue]

@snazy2000 #63 He want to get the follow each other state.

[snazy2000]

@overtrue are you expecting this result

IF NOT NULL then set field = 1
IF NULL then set field = 0 ?

Or am I miss understanding?

[snazy2000]

If the above is correct then this should work?

(CASE WHEN [pivot_followables].[user_id] IS NOT NULL THEN 1 ELSE 0 END) as [pivot_each_other],

[overtrue]

Yes, but is it compatible with MySQL?

[snazy2000]

I dont have a mysql enviroment are you able to make a change and test that and i can test mssql?  Sent from Yahoo Mail for iPhone On Thursday, November 1, 2018, 1:31 am, 安正超 <[email protected]> wrote: Yes, but is it compatible with MySQL? — You are receiving this because you were mentioned. Reply to this email directly, view it on GitHub, or mute the thread.

[snazy2000]

Looking online case is supported in mysql in select statement so does look like would work Sent from Yahoo Mail for iPhone On Thursday, November 1, 2018, 1:31 am, 安正超 <[email protected]> wrote: Yes, but is it compatible with MySQL? — You are receiving this because you were mentioned. Reply to this email directly, view it on GitHub, or mute the thread.

[overtrue]

@snazy2000 plz take a try with master branch.

[snazy2000]

No More errors! :) See query below

select [users].*, (CASE WHEN [pivot_followables].[user_id] IS NOT NULL THEN 1 ELSE 0 END) as [pivot_each_other], [followables].[followable_id] as [pivot_followable_id], [followables].[user_id] as [pivot_user_id], [followables].[followable_type] as [pivot_followable_type], [followables].[relation] as [pivot_relation], [followables].[created_at] as [pivot_created_at] from [users] inner join [followables] on [users].[id] = [followables].[user_id] left join [followables] as [pivot_followables] on [pivot_followables].[followable_type] = 'App\Suggestion' and [pivot_followables].[followable_id] = [followables].[user_id] and [pivot_followables].[user_id] = [followables].[followable_id] where [followables].[followable_id] = '1095' and [followables].[followable_type] = 'App\Suggestion' and [followables].[relation] = 'follow'

[overtrue]

😆