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ktamiola avatar ktamiola commented on May 28, 2024
  1. shift the propensity scores by -2.0, so that you are working in -1.0; 1.0 range
  2. compute the 1.0-abs(shifted_propensity_score)

That's it! The probability of disorder is simply proportional to absolute propensity score.

Please read our preprint: http://biorxiv.org/content/early/2017/06/01/144840 We have explained how to use the disorder probability in the results section.

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 avatar commented on May 28, 2024

@ktamiola sorry, I have read the paper today and understood the formulation, but suddenly forgot it for a while. My silly mistake, and thanks for remembering...

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ktamiola avatar ktamiola commented on May 28, 2024

Pleasure buddy! It's a relatively long thing to read! Allow me to tick this off the list and close the issue. Please reopen if more disordered questions come to your mind.

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 avatar commented on May 28, 2024

But what about missing values, which are zero without the -2 shift?! How does your formula handle it? By this formula, the probability of missing values is -1! Too complicated indeed!
Of course, we can filter such missing values, but process is a bit untidy.

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ktamiola avatar ktamiola commented on May 28, 2024

@ErmiaAzarkhalili missing values are always a pain in the neck. One of the approaches is to back-compute and extrapolate missing values (obviously this is up to user), or use binary weights during model training in Keras.

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