some cases of argname don't know how to deal about python-varname

[wulidongdong]

I have read other issues, it seems to be solved by wrapper.

from varname.helpers import Wrapper

def test(a=None, b=None, c=None):
    for i in b:
        print(i.name, i.value)

x = Wrapper([[111]])
y = Wrapper([[222]])
z = [x, y]
test(a=x,b=z,c=y) # x [[111]] y[[222]]

and exec can work!

test_str = 'test(a=x,b=z,c=y)'
exec(test_str) # x [[111]] y[[222]]

cool, although I do not know why it can work

[pwwang]

Remember that argname() gets what directly pass to the function. So test(a=x,b=z,c=y) is supposed to return 'z'. To get [x,y] for test(a=x,b=[x,y],c=y), you need:

def test(a=None, b=None, c=None):
    return argname('b', vars_only=False)

exec('test(a=x,b=[x,y],c=y)') won't work because we are not able to retrieve the source/AST at runtime.

---

The solution you posted later does not use the source/AST when test is called (because you don't call argname inside). If you did mean argname, then test(a=x,b=z,c=y) should return z. Anyway, it is a good solution if it meets your need.