Comments (2)
Hello,
There is currently no in-built way to do this, it would require getting the table and index data which is a list of lists, the sublists are rows, sorting this and then setting the table and index data to the newly sorted data
Once you have the data from the table a basic way of sorting the list of lists by a column would be something like this:
https://stackoverflow.com/a/4174955/7655687
There are more advanced methods which take into account digits utilising the sort()
methods key=
parameter
For example:
def sort():
col = 1
sort_key = lambda row: [
int(c) if c.isdigit() else c.lower() for c in re.split("([0-9]+)", f"{row[col]}")
]
span = sheet[:].options(index=True)
sheet.set_data(span, data=sorted(span.data, key=sort_key))
You will have to research what key you want to use as I am not experienced with sorting, natural sorting etc.
There are some libraries which handle it pretty well, for example: https://github.com/SethMMorton/natsort
I hope this helps!
from tksheet.
Is it that simple? Thank you so much for the answer and all your effort for tksheet 😀
from tksheet.
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from tksheet.