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VictorBlomberg avatar VictorBlomberg commented on September 7, 2024 17

If you change query.get(fooId) to return query.get(fooId) (thus returning the promise), you should be able to do exactly what you want.

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Tux1 avatar Tux1 commented on September 7, 2024 3

Yes but everywhere I want to use this function, I will need to dispatch loadFooSuccess myself.
I think loadFooSuccess and loadFooError should return a promise. No ?

Finally, I find a way following your advise:

function loadFoo(fooId) {
  return dispatch => {
    dispatch(loadBarRequest());

    let query = new Parse.Query('Foo');

    return query.get(fooId)
    .then((response) => {
      const json = response.toJSON();
      dispatch(loadFooSuccess(json));
      return Promise.resolve();

    }, (error) => {
      dispatch(loadFooError(error));
      return Promise.error(error);
    });
  }
}

Is a proper way to deal with my needs ?

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gaearon avatar gaearon commented on September 7, 2024

Unfortunately I don’t quite understand what is being asked here, and can’t really help. As @VictorBlomberg said, if you return a promise, you should be able to dispatch(loadFoo(id)).then(...).

Yes but everywhere I want to use this function, I will need to dispatch loadFooSuccess myself.

You wouldn’t. If you dispatch(loadFoo(id)) and it dispatches loadFooSuccess in its code, you wouldn’t need to dispatch loadFooSuccess anywhere else.

I hope this helps. If it doesn’t, I encourage you to ask on StackOverflow because this is a bug tracker rather than a discussion board, so there is much less visibility to questions here.

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