Comments (3)
If you change query.get(fooId)
to return query.get(fooId)
(thus returning the promise), you should be able to do exactly what you want.
from redux-thunk.
Yes but everywhere I want to use this function, I will need to dispatch loadFooSuccess
myself.
I think loadFooSuccess
and loadFooError
should return a promise. No ?
Finally, I find a way following your advise:
function loadFoo(fooId) {
return dispatch => {
dispatch(loadBarRequest());
let query = new Parse.Query('Foo');
return query.get(fooId)
.then((response) => {
const json = response.toJSON();
dispatch(loadFooSuccess(json));
return Promise.resolve();
}, (error) => {
dispatch(loadFooError(error));
return Promise.error(error);
});
}
}
Is a proper way to deal with my needs ?
from redux-thunk.
Unfortunately I don’t quite understand what is being asked here, and can’t really help. As @VictorBlomberg said, if you return a promise, you should be able to dispatch(loadFoo(id)).then(...)
.
Yes but everywhere I want to use this function, I will need to dispatch loadFooSuccess myself.
You wouldn’t. If you dispatch(loadFoo(id))
and it dispatches loadFooSuccess
in its code, you wouldn’t need to dispatch loadFooSuccess
anywhere else.
I hope this helps. If it doesn’t, I encourage you to ask on StackOverflow because this is a bug tracker rather than a discussion board, so there is much less visibility to questions here.
from redux-thunk.
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