fails opening a folder about fs.googledrivefs

[msb]

My case is similar to @simonm3 - I have a credentials for a service account that has permission on a GCP folder. The folder would have to be referenced by a file id but it isn't clear to me how this would be done using either fs.opendir() or a path.

[rkhwaja]

Going by the code in your other issue, I think that the format of your URI is wrong - the "?access_token=..." part has to be at the end, after the subdirectory part.

[rkhwaja]

Is GCP is a different service? This project supports "Google Drive". There's another pyfilesystem plugin called fs-gcsfs which supports "Google Cloud Storage"

[simonm3]

@rkhwaja you may be right about the format. however this still only opens the root folder. code below lists the root folder contents.

gd = fs.open_fs(f"googledrive://eedata/{creds.gdrive()}")
gd.listdir("/")

[simonm3]

It works if I add an extra slash fs.open_fs(f"googledrive:///eedata/{creds.gdrive()}")

However the pyfilesystem url does not have a slash at the start of a folder in the examples https://docs.pyfilesystem.org/en/latest/openers.html

[simonm3]

Also the format shown in documentation is creds@resource.

Ideally the creds should be in similar format regardless of file system used. So for google drive API they should appear before the resource and googledrivefs should convert that into whatever format google uses.

[msb]

My mistake - I should have written Google Drive folder (it's the service account that is part of the Google Clouds Platform). My use case is supported by the native Drive API - it's a method for a user to grant an application permission to work on a sub-set of the user's files.

[rkhwaja]

My case is similar to @simonm3 - I have a credentials for a service account that has permission on a GCP folder. The folder would have to be referenced by a file id but it isn't clear to me how this would be done using either fs.opendir() or a path.

My case is similar to @simonm3 - I have a credentials for a service account that has permission on a GCP folder. The folder would have to be referenced by a file id but it isn't clear to me how this would be done using either fs.opendir() or a path.

Since this project is a plugin for pyfilesystem2, it only uses "paths", although I suppose that the definition of that is somewhat up to the individual plugins - I'm not sure how far you can push that. We can add custom methods that do something specific with the filesystem (e.g. add_parent, remove_parent) but that aren't relevant to filesystems in general.

[msb]

Thanks for your response @rkhwaja. I have made a fork and implemented support for a sub-tree specified by an ID. I have also used it in an example project with an explanatory readme. I've had second thoughts about the approach in the fork and think maybe the root directory could better be specified by a parameter (say root_dir_id) passed to the GoogleDriveFSOpener. If you like this idea, I'm happy to re-work and create a CR.