Comments (7)
When you get a service from DI container you should define the returned value as Logger interface from winston.
import winston from 'winston';
const Logger = Container.get('logger') as winston.Logger;
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Similar to @dzianisreznik's answer:
import { Logger } from 'winston';
const logger: Logger = Container.get('logger');
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We need to do JSON.parse(Container.get('logger')) to remove error. It is in many files. Any generic way to solve this problem?
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Hi!
Let me investigate this and will get back to you
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Instead of directly importing this - import { Container } from 'typedi'; we can create a wrapper over this and that wrapper will return us the parsed version of object. What do you say?
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What's the update on this?
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@dzianisreznik and @bjfletcher this approach solves the problem.
Though without importing Logger
, I used @ts-ignore
like the following and it also resolved the problem though it was not neat and I don't like it.
const logger = Container.get("logger");
// @ts-ignore
logger.info("Breaking Log");
Now with your solutions, I was wondering if I'm getting the instance from Container
then are we using
import { Logger } from 'winston';
just to tell typescript that the instance we are pulling out from the DI container is of type Logger
?
And does not import { Logger } from 'winston';
this line also import Logger
codes from winston
? Does not this increase the file size when transpiling?
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