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QuentinRoy avatar QuentinRoy commented on May 30, 2024 1

It is probably a better approach then, because my solution currently has issues when exporting. But would it mean the program would only show the result once all setTimeout are done? I was currently thinking about overriding setTimeout in print mode and so have a fully different behavior in this case. But it starts to feel rather hacky.

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KermanX avatar KermanX commented on May 30, 2024

The code is runned in a async context currently. You can use the await keyword on top level. However, setTimeout isn't working because the program finished before the callback, then the results aren't shown.

It is possible to override setTimeout in the running context, so that the program will only be regarded finished after all timeouts got triggered.

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KermanX avatar KermanX commented on May 30, 2024

But would it mean the program would only show the result once all setTimeout are done?

Yes. And we can improve this in the future.

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