sminnee / dysphasia Goto Github PK
View Code? Open in Web Editor NEWToy programming language as a learning exercise.
Toy programming language as a learning exercise.
In the following example:
main {
for(x in [1..5]) {
puts(square(x));
}
}
square(x) => x*x;
The following type inferences should be made:
Conflicts should throw a syntax error.
IntelliJ sanity inspector gives all red squiggly lines.
In this example:
main {
puts(square(2));
puts(square(3.5));
}
}
square(x) => x*x;
The following type inferencing should occur:
square(x)
should first be inferred to be int(int)
float(float)
Internally the the code should get transformed to something like this:
main {
puts(int square<int>(2));
puts(float square<float>(3.5));
}
}
T square<T>(T x) => x*x;
// expanded
int square<int>(int x) => x*x;
float square<float>(float x) => x*x;
Note: It might be easier if all method calls have type suffixes added to them, regardless of whether there are multi-type calls.
Although mutable variables are something I'd like to stay away from initially, single-assignment variables should be supported, to do stuff like this:
main {
x = [1,4,9,5];
for(i in x) {
printf("x[%i] = %i", i, x[i]);
}
}
Once compiled, the printf should probably still refer directly to a const array.
Amend the range synax to use [
and ]
. It will make chaining easier. Implement array.map, using a lambda as a function argument.
main {
for(i in [1..5].map(x | x*x)) puts(i);
}
Add support for lambdas, as a first step towards adding array.map. Could use arrow or guard syntax. While we're add it, allow single-statement for loops, for the example below :-)
main {
int(int) square = (x) => x * x;
int(int) cube = (x | x * x * x);
for(i in 1..5) puts(square(i));
for(i in 1..5) puts(cube(i));
}
Don't worry about closure variable binding for now.
Two features:
The following script:
x = [1, 2, 3, 5];
y = x * 2;
z = y * y;
for(i in z) {
puts(i);
}
Should output:
4
16
36
100
Let's add a companion to array.map and we can bask in our functional goodness.
main {
square = (x) => x*x;
sum = (x) => x+x;
sumSquares = a => a.map(square).reduce(sum);
puts(sumSquares([1,2,3])); // 14
}
Ideally, the output of map can be piped into reduce without first creating an intermediary array, so that the compiled code is more of this form:
sumSquares(a) {
for(i in a) {
mapped = i*i;
reduced = reduced+mapped;
}
return reduced;
}
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