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hkpeprah avatar hkpeprah commented on June 9, 2024

Ah, okay. I think I get it. Is your suggestion to treat the xs as wildcards, and then match them? E.g.

>>> re.findall(re.sub(r'x', '.', 'MIMXRT1064xxx5A'), 'MIMXRT1064CVL5A')
['MIMXRT1064CVL5A']

I think we'd have to be careful to make sure that we're converting only multiple occurrences of lowercase x, but I don't see why not. I'm not too much of a regex expert though to craft the appropriate substitution, but I welcome a patch if you want to take a stab at it.

from pylink.

 avatar commented on June 9, 2024

from pylink.

 avatar commented on June 9, 2024

from pylink.

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