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StefanTerdell avatar StefanTerdell commented on May 23, 2024

This one's a little trickier than you'd initially expect. Whether or not a property with a default value should be required or not basically comes down to which JSON Schema validator you use. The only single source of truth that I know of comes from the other side of the equation - Zod itself.

import { z } from "zod";

const schema = z.object({ requiredProperty: z.string().default("some value") });

type Input = z.input<typeof schema> // { requiredProperty?: string | undefined }
type Output = z.output<typeof schema> // { requiredProperty: string }

const data = schema.parse({}) // This is fine

console.log(data); // { requiredProperty: "some value" }

Due to design decisions made for the Zod API we can't target the output type (aka infer), only the input type.

Unless there is a part of the JSON Schema specification (which I may well have missed) that defines this behavior conclusively I'm leaning towards keeping it as is.

from zod-to-json-schema.

ciscoheat avatar ciscoheat commented on May 23, 2024

Ok, and with Superforms targeting the output type is the primary thing, or at least has been for version 1. But I'll take this into consideration for sure, thank you. Would it still be possible to add it as an option, even though you're focusing on the input type? If it's too much work or goes against your design, no problem.

from zod-to-json-schema.

StefanTerdell avatar StefanTerdell commented on May 23, 2024

Well, Zod allows chaining transformational functions into the schemas that affect the output type, and those obviously can't be serialized. So it's not really up to me unfortunately :/

However, if you wanted to really target this specific use-case, you could rebuild the way optionality is checked in the object parser and add an option to ignore default values there. I'd be open to a PR for it. I might even take a stab at it myself at some point but I'm not making any promises.

from zod-to-json-schema.

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