Default time for incomplete datetime strings about dateparser

[waltzofpearls]

Yes. I think parse_with function will help you do that.

Below is an example showing you how to pass a default time to the function call. To replicate what Joda does, you can call dateparser::parse_with("2021-12-02", &chrono::offset::Utc, chrono::naive::NaiveTime::from_hms(0, 0, 0))?, and it should return 2021-12-02T00:00:00Z as type chrono::DateTime<chrono::offset::Utc>.

use chrono::{
    naive::NaiveTime,
    offset::{Local, Utc},
};
use dateparser::parse_with;
use std::error::Error;

fn main() -> Result<(), Box<dyn Error>> {
    let parsed_in_local = parse_with("2021-10-09", &Local, NaiveTime::from_hms(0, 0, 0))?;
    println!("{:#?}", parsed_in_local);

    let parsed_in_utc = parse_with("2021-10-09", &Utc, NaiveTime::from_hms(0, 0, 0))?;
    println!("{:#?}", parsed_in_utc);

    Ok(())
}

Since that example is in the repo, you can run it with cargo run --example parse_with.

For future v1 release, I'm going to make 00:00:00Z as default time for parse function, so it will be aligned with date parser libraries from other languages.

[nheitz]

Brilliant. How nice when the API already caters for the need at hand! I appreciate your response...I was in despair with the rigidity of the base chrono offerings before I discovered this library.

[waltzofpearls]

I couldn't agree more. I struggled when writing this library with chrono's docs, as it only has examples for common use cases. I had to read chrono source code to figure out how to made it doing things I wanted.

I will leave this issue open for 24 hours in case if you have further questions.