Comments (2)
I also feel the answer is wrong. Here is my proposing solution.
#include <ctype.h>
void capitalize(char *str) {
char *c = str;
while (*c != '\0') {
if (isalpha(*c))
*c = toupper(*c);
c++;
}
}
from c-solutions.
I virtually have the same answer, only without the if statement. I'm not sure, but I think toupper() only does something to characters in the alphabet so the isalpha() call would be redundant.
// using pointer arithemtic
void capitalize2(char *str)
{
char *p = str;
while(*p != '\0')
{
*p = toupper(*p);
*p++;
}
*p = '\0';
printf("%s", str);
}
from c-solutions.
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