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zhuchen03 avatar zhuchen03 commented on July 20, 2024

Thank you for your interest! We'll get it ready before June 8.

from convexpolytopeposioning.

zxydi1992 avatar zxydi1992 commented on July 20, 2024

Thank you for your interest! We'll get it ready before June 8.

Btw, I'd like to implement some part of the Algorithm 1. I wonder how you check the convergence with the two "while" statements. Plus, is it | A^TA |_2 = \sqrt{\sum_i, j c{i,j}^2}? (C=A^TA)

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zhuchen03 avatar zhuchen03 commented on July 20, 2024

Yes we are using | A^TA |_2 = \sqrt{\sum_i, j c{i,j}^2} in our implementation. The goal of setting step size to alpha=1/| A^TA |_2 is to make it smaller than 2/M so that the convex optimization problem is guaranteed to converge, where M is the Lipschitz constant of the gradient. In this problem, M should be equal to the l2 operator norm of A^TA, but the Frobenius is an upper bound of M and is easier to compute.

For the inner while loop, we just need to observe whether the objective value changes less than a threshold after one update step. For the outer loop, usually we just set a fixed number of iterations enough for convergence.

from convexpolytopeposioning.

zxydi1992 avatar zxydi1992 commented on July 20, 2024

Yes we are using | A^TA |_2 = \sqrt{\sum_i, j c{i,j}^2} in our implementation. The goal of setting step size to alpha=1/| A^TA |_2 is to make it smaller than 2/M so that the convex optimization problem is guaranteed to converge, where M is the Lipschitz constant of the gradient. In this problem, M should be equal to the l2 operator norm of A^TA, but the Frobenius is an upper bound of M and is easier to compute.

For the inner while loop, we just need to observe whether the objective value changes less than a threshold after one update step. For the outer loop, usually we just set a fixed number of iterations enough for convergence.

That helps a lot. Thanks.

from convexpolytopeposioning.

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