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jdata-rank37

京东JData算法大赛Rank37

jdata_

如期而至-用户购买时间预测

kaggle

kaggle-ensemble-guide

Code for the Kaggle Ensembling Guide Article on MLWave

kaggle-quora

Kaggle Quora Questions Pairs Competition

kaggle-quora-question-pairs

Kaggle：Quora Question Pairs, 4th/3396 (https://www.kaggle.com/c/quora-question-pairs)

kaggle-quora-question-pairs-1

This is our team's solution report, which achieves top 10% (305/3307) in this competition.

kaggle-quora-question-pairs-2

My solution to Kaggle Quora Question Pairs competition (Top 7%, 209th of 3307).

kaggle-quora-solution-8th

kaggle-toxic_comment

Code for Kaggle Jigsaw Toxic Comment, 34th / 4551 (Top 1%) Solution

kaggle_criteo_ctr_challenge-

This is a kaggle challenge project called Display Advertising Challenge by CriteoLabs at 2014.这是2014年由CriteoLabs在kaggle上发起的广告点击率预估挑战项目。

kesci_ctrip

用户预订售卖房型概率预测--top1

leetcode

http://wepe.github.io/LeetCode/

linkprediction

Solution for Tsinghua Data Science Winter School 2017

machinelearningtrick

Machine Learning Trick : GBDT_Feature Blending Stacking CascadeForest

ml

nlp-demo

nlp相关实验

nlu_sim

all kinds of baseline models for sentence similarity

o2o-coupon-usage-forecast

1st Place Solution for O2O Coupon Usage Forecast

o2o-predict-coupon-usage

天池O2O优惠券使用预测第一赛季部分代码

paraphrase-id-tensorflow

Various models and code (Manhattan LSTM, Siamese LSTM + Matching Layer, BiMPM) for the paraphrase identification task, specifically with the Quora Question Pairs dataset.

pcvr

第一届腾讯社交广告-高校算法设计大赛。

practice

some practice

python_data_science_by_iris

iris数据集的基本数据分析方法，包括KNN,LG,NB,SVM算法。

quora-question-pairs

My solution to Kaggle Quora Question Pairs competition (Top 20%, Public LB log loss 0.17539 and Private LB log loss 0.17220).

rental-listing-inquiries

kaggle:Two Sigma Connect: Rental Listing Inquiries--top1

seq2seq

Sequence to Sequence Learning with Keras

sklearn-introduction

3节课简单入门一下sklearn

smpcup2016

2nd Place Solution for SMP CUP 2016

ssd_pytorch

support different SSDs and different scale test, support refineDet.