Memory leaks / Free on address which was not malloc()-ed about orcania

[babelouest]

I think the memory leak's on you, in your code you update the value of arr before cleaning it, therefore, when you call free_string_array, the pointer is not the one that was allocated.

This should work better:

int main() {
    char **arr, ** save;
    split_string("abc 123", " ", &arr);
    save = arr;
    while (*arr) {
        printf("%s\n", *arr);
        arr++;
    }
    free_string_array(save);
    return 0;
}

[silvioprog]

Thanks for clarifying it. :-)

I'm inspired in these functions to create a command line parser supporting the following styles:

some/command arg1 'arg2' "arg3" "arg4 somevalue"

the final array will be:

some/command
arg1
arg2
arg3
arg4 somevalue

and

some/command \
  arg1 \
  'arg2' \
  "arg3" \
  "arg4 somevalue"

the final array will be:

some/command
arg1
arg2
arg3
arg4 somevalue