cuedo / rot13

Haskell implementation of the rot13 substitution cipher.

License

MIT License

Copyright (c) 2017-2020 Cuedo Business Solutions (https://cuedo.com.au)

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of this software and associated documentation files (the "Software"), to deal
in the Software without restriction, including without limitation the rights
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Free open source software, sponsored by cuedo.com.au.

rot13's Issues

rot13-0.2.0.0 test suite build failure

As seen on stackage server:

Preprocessing test suite 'spec' for rot13-0.2.0.0...
[1 of 1] Compiling Main             ( test/Spec.hs, dist/build/spec/spec-tmp/Main.o )

test/Spec.hs:20:7: error:
    • Ambiguous type variable ‘c0’ arising from a use of ‘property’
      prevents the constraint ‘(Arbitrary c0)’ from being solved.
      Probable fix: use a type annotation to specify what ‘c0’ should be.
      These potential instances exist:
        instance [safe] (Arbitrary a, Arbitrary b) =>
                        Arbitrary (Either a b)
          -- Defined in ‘Test.QuickCheck.Arbitrary’
        instance [safe] Arbitrary Ordering
          -- Defined in ‘Test.QuickCheck.Arbitrary’
        instance [safe] Arbitrary Integer
          -- Defined in ‘Test.QuickCheck.Arbitrary’
        ...plus 19 others
        ...plus 32 instances involving out-of-scope types
        (use -fprint-potential-instances to see them all)
    • In the second argument of ‘($)’, namely
        ‘property $ \ s -> s == (rot13 . rot13) s’
      In a stmt of a 'do' block:
        it "is reversible" $ property $ \ s -> s == (rot13 . rot13) s
      In the second argument of ‘($)’, namely
        ‘do { it "correctly ciphers the alphabet"
              $ do { rot13 "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz"
                     `shouldBe`
                       "NOPQRSTUVWXYZABCDEFGHIJKLMnopqrstuvwxyzabcdefghijklm" };
              it "is reversible" $ property $ \ s -> s == (rot13 . rot13) s }’


test/Spec.hs:20:24: error:
    • Ambiguous type variable ‘c0’ arising from a use of ‘==’
      prevents the constraint ‘(Eq c0)’ from being solved.
      Relevant bindings include s :: c0 (bound at test/Spec.hs:20:19)
      Probable fix: use a type annotation to specify what ‘c0’ should be.
      These potential instances exist:
        instance (Eq b, Eq a) => Eq (Either a b)
          -- Defined in ‘Data.Either’
        instance Eq Ordering -- Defined in ‘ghc-prim-0.5.0.0:GHC.Classes’
        instance Eq Integer
          -- Defined in ‘integer-gmp-1.0.0.1:GHC.Integer.Type’
        ...plus 23 others
        ...plus 162 instances involving out-of-scope types
        (use -fprint-potential-instances to see them all)
    • In the expression: s == (rot13 . rot13) s
      In the second argument of ‘($)’, namely
        ‘\ s -> s == (rot13 . rot13) s’
      In the second argument of ‘($)’, namely
        ‘property $ \ s -> s == (rot13 . rot13) s’

test/Spec.hs:20:30: error:
    • Ambiguous type variable ‘c0’ arising from a use of ‘rot13’
      prevents the constraint ‘(Rot13 c0)’ from being solved.
      Relevant bindings include s :: c0 (bound at test/Spec.hs:20:19)
      Probable fix: use a type annotation to specify what ‘c0’ should be.
      These potential instances exist:
        instance Rot13 Integer -- Defined in ‘Codec.Rot13’
        instance Rot13 Char -- Defined in ‘Codec.Rot13’
        instance Rot13 Int -- Defined in ‘Codec.Rot13’
        ...plus two others
        ...plus 22 instances involving out-of-scope types
        (use -fprint-potential-instances to see them all)
    • In the first argument of ‘(.)’, namely ‘rot13’
      In the expression: rot13 . rot13
      In the second argument of ‘(==)’, namely ‘(rot13 . rot13) s’

I was able to reproduce on my local machine like so:

$ stack unpack rot13-0.2.0.0 && cd rot13-0.2.0.0
$ stack init --resolver nightly-2017-07-10
$ stack test