linehk / gopl

gopl(The Go Programming Language) is a project that contains all the sample code and all exercise answers in the Go Programming Language.

gopl

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gopl(The Go Programming Language) is a project that contains all the sample code and all exercise answers in the Go Programming Language.

The Go Programming Language

ISBN: 978-0134190440

Installation

apt-get install libbz2-dev
git clone https://github.com/linehk/gopl.git

Contributing

If you feel that there is something to improve my exercise answers, please feel free to launch Pull Request.

For major changes, please open an issue first to discuss what you would like to change.

License

MIT License

Greetings

Happy Go programming, I hope you enjoy writing Go as much as I do.

gopl's Issues

import "C" regenerate cgo definitions

ch13\biz\bzip2.go里面的出现这个import "C" regenerate cgo definitions应该怎么处理

练习1.4似乎有错误，题意是打印出现了重复行的文件，而不是打印程序的名字。

找到了一个正确的答案：ex1.4

ch2-exercise2.2 undefined: Celsius

go run main.go -weight 33如果直接运行提示

 command-line-arguments
./main.go:55:37: undefined: Celsius
./main.go:55:52: undefined: CToK
./main.go:55:57: undefined: Celsius
./main.go:63:50: too many errors

正确执行 �cd ch2/exercise2.2 && go build 构建成可执行文件后 ./exercise2.2 -weight 33

exercise2.5/popcount.go 去掉&之后运行很慢

gopl/ch2/exercise2.5/popcount.go

Line 28 in 8de9286

x &= x - 1

如果去掉 & 变成 x = x - 1 那么执行变得很慢

是不是去掉之后每次循环都需要开辟一块内存空间导致程序慢的?

ch1-dup1运行卡住了?

1. 创建一个文件text当前目录 输入几行内容
2. 当前目前执行命令 cat text | go run main.go
   tip: 如果是在命令行直接运行go run main.go, 程序是走到Scan()一直等待用户的输入 不会往下走了

e1.3执行基准测试输出大量 test.paniconexit0 -test.timeout是正常的吗

这个输出的内容是正常的吗？ 如果是正常的话 可以不输出这些内容只输出最后的结果吗？

操作步骤
cd gopl/ch1/exercise1.3

go test -bench=.

输出下面内容

....
-test.paniconexit0 -test.timeout=10m0s -test.bench=.
-test.paniconexit0 -test.timeout=10m0s -test.bench=.
-test.paniconexit0 -test.timeout=10m0s -test.bench=.
-test.paniconexit0 -test.timeout=10m0s -test.bench=.
-test.paniconexit0 -test.timeout=10m0s -test.bench=.
-test.paniconexit0 -test.timeout=10m0s -test.bench=.
-test.paniconexit0 -test.timeout=10m0s -test.bench=.
-test.paniconexit0 -test.timeout=10m0s -test.bench=.
-test.paniconexit0 -test.timeout=10m0s -test.bench=.
-test.paniconexit0 -test.timeout=10m0s -test.bench=.
-test.paniconexit0 -test.timeout=10m0s -test.bench=.
....

ch7-ex7.1中为什么是len(p) 而不是c呢

gopl/ch7/exercise7.1/main.go

Lines 20 to 30 in 8de9286

	type WordCounter int
	func (c *WordCounter) Write(p []byte) (int, error) {
	scanner := bufio.NewScanner(bytes.NewReader(p))
	scanner.Split(bufio.ScanWords)
	for scanner.Scan() {
	*c++
	}
	return len(p), nil
	}

exercise4.1 中的与比较问题

这儿为什么是要与后比较, 而不能是直接 b1 != b2

gopl/ch4/exercise4.1/main.go

Line 26 in 8de9286

if b1&mask != b2&mask {

练习9.3的并发安全问题

练习9.3的并发安全问题

会不会发生并发安全问题
t1,t2是两个协程
步骤一 t1 首次访问 mi.com
执行首次查询
步骤二 t1 查询终止
done返回终止消息，删除map中对应的value，关闭通道，进行广播
步骤三 t2 此时访问访问 mi.com 读map

步骤二和步骤三可能会同时对map的同一个Key进行读写，这里是不是没有进行并发处理

题目 判断两个字符串是否是相互打乱 那如何两个字符串完成相等也返回true 是否是一个BUG~

gopl/ch3/exercise3.12/main.go

Line 11 in 8de9286

func isAnagram(s1, s2 string) bool {

如果是可以PR一个~

if s1 == s2 {
   return false
}

你这答案错误有点多啊，误人子弟