backoff.expo base about backoff

[tasercake]

I think the equation itself makes sense as it is.

In

a = factor * (base ** n)

base is the component that's exponentiated, and the result is scaled by factor.
There might be some confusion due to the lack of parentheses in the source.

If I'm not mistaken, it looks like the only change required here is to set n = 1, although you could simply adjust factor to get whatever starting value you'd like.

[bgreen-litl]

Sorry for the slow response - I was away last week.

You may be right that it should be

a = base * factor ** n

but I need to refresh my thinking about base and factor - I believe those were included when adding support for the jitter algorithm from https://www.awsarchitectureblog.com/2015/03/backoff.html

I will get back to you when I have a few minutes to investigate.

[gregroberts]

Happy to submit a ludicrously small PR if you like ; )

[flaurencin]

I think the equation itself makes sense as it is.

In

a = factor * (base ** n)

base is the component that's exponentiated, and the result is scaled by factor.
There might be some confusion due to the lack of parentheses in the source.

If I'm not mistaken, it looks like the only change required here is to set n = 1, although you could simply adjust factor to get whatever starting value you'd like.

I prefer this approach.