Comments (3)
You are right @kaido42. What a shame. 😞
The problem is, that I simply sum up the byte values of the characters. 'a' is 97, 'b' is 98, and 'c' is 99.
Therefore 'a' + 'a' + 'b' + 'b' has the same sum as 'a' + 'a' + 'a+ 'c', which is 390.
What I should have done instead, is to check if the occurrences of each character match.
An O(n)
way to do that would be to go over each character in the input one-by-one and increase a counter for the character in an associative array. I do something similar in the Python solution.
Another option would be to sort the inputs and compare the characters from left to right. That would be O(n*log n)
, though.
Both options would be fine for me.
Could you make a pull request to fix that? Would be great. 😃
from the-coding-interview.
Could you make a pull request to fix that? Would be great
sry, too lazy :)
from the-coding-interview.
^^ Happy hacktober
from the-coding-interview.
Related Issues (8)
- how to runn this code
- convert-array solution is wrong HOT 2
- knights-on-chessboard python solution is wrong. HOT 5
- C array size must be passed as a second argument HOT 2
- Add condition for underflow before popping elements in stacks implementation HOT 4
- Provide solutions for other languages HOT 5
- Statistics! HOT 2
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