The rank from myin1994

rank's Introduction

客户端上传客户端号和分数(注意：并不会上传排名,客户端无法上传排名),同一个客户端可以多次上传分数，取最新的一次分数

接口：http://127.0.0.1:8000/rank/get_or_update_rank/
请求方式：POST
数据格式:JSON
{
 "uid":21,#客户端id
 "score":500 #分数
}
响应数据：暂定成功或错误状态码

视图链接

客户端查询排行榜

接口：http://127.0.0.1:8000/rank/get_or_update_rank/
请求方式：GET
数据格式:PARAMS
uid 客户端id
start end 排序起止点
响应数据：JSON
对应排序及相关信息
[
    {
        "1": {
            "uid": 4,
            "client_name": "客户端4",
            "score": 33300
        },
        "2": {
            "uid": 27,
            "client_name": "客户端27",
            "score": 6474
        },
        "3": {
            "uid": 26,
            "client_name": "客户端26",
            "score": 6454
        },
        "4": {
            "uid": 25,
            "client_name": "客户端25",
            "score": 3454
        },
        "5": {
            "uid": 24,
            "client_name": "客户端24",
            "score": 3444
        },
        "6": {
            "uid": 23,
            "client_name": "客户端23",
            "score": 3424
        },
        "7": {
            "uid": 1,
            "client_name": "客户端1",
            "score": 500
        },
        "8": {
            "uid": 2,
            "client_name": "客户端2",
            "score": 400
        },
        "9": {
            "uid": 3,
            "client_name": "客户端3",
            "score": 100
        }
    },
    {
        "8": {
            "uid": 2,
            "client_name": "客户端2",
            "score": 400
        }
    }
]

附加题

from itertools import zip_longest

version1 = "1.0"
version2 = "1.0.0"

def compareVersion(version1, version2):
    f = lambda x: map(int, x.split('.'))
    for v1, v2 in zip_longest(f(version1), f(version2), fillvalue=0):
        if v1 != v2:
            return 1 if v1 > v2 else -1
    return 0
ret = compareVersion(version1,version2)
print(ret)

Recommend Projects