Non-greedy operators for * , + , and ? about pegjs

[dmajda]

In PEG formalism, you can easily match until a terminator by using a predicate together with the . metacharacter. Something like:

"OBJECT IDENTIFIER" (!"}" .)* "}"

Is that sufficient for you?

[curvedmark]

#66 will fix this.

I think in the mean while you can use:

rule
    = chars:(!"-suffix" c:. {return c})+ "-suffix"

[richb-hanover]

Update: This could be satisfied by a repetition count (which is a generalization of my initial thought) as suggested in Google Groups at: http://groups.google.com/group/pegjs/browse_thread/thread/2bea15581be45187

[richb-hanover]

Yes, that works perfectly. Thanks!

[rymohr]

@dmajda What's the recommended practice for stripping out the empty char returned by the !"}" expression?

For example:

rule
   = chars:(!"-suffix" .)+ "-suffix"

"foo-suffix" => [[ '', 'f' ], ['', 'o' ], ['', 'o' ]]  // result
"foo-suffix" => ['f', 'o', 'o' ] // desired result

I was able to achieve this by breaking !"-suffix" . into its own rule that just returns the . result, but I'm curious if there's a better way.

[dmajda]

@islandr Please don't use issues as a place to ask questions about PEG.js usage. Especially when they are closed and especially when you are asking something that other people beside me can help you with. The proper channel is the Google Group.

[rymohr]

Sorry David. Thought this would have been a good place since it was
directly related to the example you'd given.

On Wed, Jan 9, 2013 at 9:51 PM, David Majda [email protected]:

@islandr https://github.com/islandr Please don't use issues as a place
to ask questions about PEG.js usage. Especially when they are closed and
especially when you are asking something that other people beside me can
help you with. The proper channel is the Google Grouphttp://groups.google.com/group/pegjs
.

—
Reply to this email directly or view it on GitHubhttps://github.com//issues/57#issuecomment-12083927.