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利用最短路径算法(Dijkstra) 生成懒人键盘字典

猪猪侠在zone中提出了利用最短路径算法(Dijkstra) 生成懒人键盘字典这个挑战

现在脚本已知的不足：

  • 在计算1到x最短路径时，只得出12wsx,而得不出1qwsx、1qasx、1qazx这三种路径(估计还得写个二叉树...不过3个键位及4个键位的最短路径不受影响)

脚本的一些用法：

  • 修改第99行的条件，即可修改生成的密码组合的键数
if len(z)==4 or len(z)==3:

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