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Management command to start an app with class-based views. You use "python manage.py startcbv <appname>". It's very fresh and unstable, so use at your own risk, but it does work!

License: MIT License

django-startcbv's Introduction

django-startcbv

Installation

Add django-startcbv==0.1 to requirements.txt, then just:

pip install -r requirements.txt

Usage

For all of the following steps, replace "things" with the name of the app that you wish to create:

python manage.py startcbv things

Add your "things" app to INSTALLED_APPS in settings.py:

INSTALLED_APPS = (
    ...
    'things',
)

Add your "things" app URL pattern to urls.py:

url(r'^things/', include('things.urls')),

Then:

python manage.py syncdb
python manage.py runserver

License

This code is licensed under the MIT License.

django-startcbv's People

Contributors

audreyfeldroy avatar pydanny avatar

Stargazers

Philippe Ombredanne avatar

Watchers

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