💌 Communication through AdafruitIO feed

We'll be trying to communicate through a shared Adafruit IO feed using a button and an esp8266 NodeMCU board. One person will press the button, and then the other person should be able to see the inputs on their screen. This way we'll be able to say hi! 👋

📆 Date: 12/10/2022

What do you need for this?

Adafruit IO account
esp8266 NodeMCU board
A button
Wifi (not 5G)

💻 1 - New feed

Log into your Adafruit IO account and create a new feed. We named our feed 'kussiekussielove'.

To create a shared feed, open your feed and click Sharing. Invite the other person to your feed with their email and don't forget to give them READ + WRITE rights.

🛎️ 2 - Button

Connect the button to your board. We connected our button to D0 (red = 3.3, black to gnd, yellow to D0).

🔮 3 - Code

Open your Arduino IDE and open an example sketch from Examples > adafruit io > Adafruitio_06_digital.in Change the BUTTON_PIN to the one you're using, in our case we changed it to BUTTON_PIN D0. Also put in your adafruit key and wifi password, you can do this in the config.h tab. Now your code is ready to go! 🎉

#define BUTTON_PIN D0

// button state
bool current = false;
bool last = false;

// set up the 'digital' feed
AdafruitIO_Feed *digital = io.feed("digital");

void setup() {
  // set button pin as an input
  pinMode(BUTTON_PIN, INPUT);

  // start the serial connection
  Serial.begin(115200);

  // wait for serial monitor to open
  while(! Serial);

  // connect to io.adafruit.com
  Serial.print("Connecting to Adafruit IO");
  io.connect();

  // wait for a connection
  while(io.status() < AIO_CONNECTED) {
    Serial.print(".");
    delay(500);
  }

  // we are connected
  Serial.println();
  Serial.println(io.statusText());
}

void loop() {
  // io.run(); is required for all sketches.
  // it should always be present at the top of your loop function. 
  // it keeps the client connected to io.adafruit.com, and processes any incoming data.
  io.run();

  // grab the current state of the button.
  // we have to flip the logic because we are using a pullup resistor.
  if(digitalRead(BUTTON_PIN) == LOW)
    current = true;
  else
    current = false;

  // return if the value hasn't changed
  if(current == last)
    return;

  // save the current state to the 'digital' feed on adafruit io
  Serial.print("sending button -> ");
  Serial.println(current);
  digital->save(current);

  // store last button state
  last = current;
}

📩 4 - Upload & check

Upload your code. Check your serial monitor to see if the button is working properly. It should say: "sending button ->", when the button input is being sent to your shared feed.

Then go to your Adafruit IO feed and check if you get a signal from the button.

🚩 Error

Nothing happened when we pressed the button! We could see the confirmation message in the serial monitor, so we thought there must be a problem connecting to adafruit. We checked our code and found out we forgot to put in our feed name. Ofcourse it cannot connect to a feed it doesn't know. We had to refer to our feed like this:

AdafruitIO_Feed *digital = io.feed("kussiekussielove");

It works! 🎉

Now you can see the button input on your shared feed. It should look something like this:

🗃️ Sources:

https://learn.adafruit.com/adafruit-io-basics-feeds/sharing-a-feed

rarooij98 / communication-through-adafruitio-feed Goto Github PK