Android开发实践专栏代码仓库
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Home Page: https://www.yuque.com/nongxiangang/androidsample
License: GNU General Public License v3.0
Android开发实践专栏代码仓库
Home Page: https://www.yuque.com/nongxiangang/androidsample
License: GNU General Public License v3.0
box中倒是有一个 (gameState == GameState.Over) 的判断,设成透明了,但是这样在非over的state下点击退出按钮所在的位置(此时按钮alpha为0,看不见,但是点击事件能相应),就可以直接退出了,当时无意间点了一下,直接退出了,还以为是崩溃,有点懵逼..
不过以上不是重点,我觉得只是作者疏忽了,我真正想请教的是,当我把退出按钮的 onClick 改为 onClick = { if (gameState == GameState.Over) gameAction.exit },居然点击没有反应,emm.. 不能说没有反应,准确说,应该是 gameAction.exit 函数执行没有效果,然后我试了一下,与前面的 if 判断没有关系,只要是 onClick 的内容用大括号括起来,它的执行就没有效果,让我有点费解。对 Flow 的了解不深,希望您能解答一下,感谢。
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